Chemistry Homework #2
Answer Key
 

Problems from Kotz & Treichel

35a) Six emission lines are possible. These are:

n = 4 ® n = 3;    n = 4 ® n = 2;    n = 4 ® n = 1

n = 3 ® n = 2;    n = 3 ® n = 1

n = 2 ® n = 1


b) The n = 4 ® n = 1 transition will have the highest energy.
 

c) The n = 4 ® n = 3 transition will have the longest wavelength.
 

41) The lowest energy line in the Pfund series corresponds to the n = 6 ® n = 5 transition. The frequency (in cm-1) is given by:
 

Using RH = 109,700 cm-1,


43) The wavelength of the electrons in the beam is given by:
 

45) The wavelength associated with the bullet is:
 


73) The shortest wavelength an excited H atom can emit arises from an n = ¥ ®n = 1 transition. The wavelength (in nm) would be:

Additional Problems:

1) The wavelength of an n = 6 ®n = 5 transition for He+ is:


An example of a transition that would yield a photon of visible light would be an n = 6 ® n = 4, which would emit 656 nm light (red).
 

2) The ionization energy of a hydrogen atom with a principal quantum number of five is: