1.     A. HI because it is larger
        B. CH₃COOH because there are more oxygens to distribute the charge
        C. HClO4 because there are more oxygens to distribute the charge
2.     pH = -log[H+]
        [H+] = 10^-8.2 = 6.3 x 10^-9 M
        basic
3.     pOH = 14 - pH = 14 - 8.2 = 5.8
        pOH = -log[-OH]
        [-OH] = 10^-5.8 = 1.6 x 10^-6 M
4.             HCNO ---->  H+   + -CNO
      start    1.0                0        0
    change   - x                + x    + x
equilibrium 1.0 -x            x        x

        K = [H+][-CNO]  = x²/1.0-x ~ x²/1.0 = 2.2 x 10^-4
                [HCNO]

        x = 0.0148 M = [H+]
        pH = -log[H+] = 1.8

5. A. 0.0762 L x 0.1 moles/L = 0.00762 moles
        0.00762 moles/0.05 L = 0.152 M
    B. 7